If two vertice of an equilateral triangle are (3,0) and (6,0) then find the third vertex
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(3,3 ) is third vertex
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Heya.... Here is ur answer
Let the third vertex be P(x, 0)
By distance formula,
PB=PA
Squareing both sides
PB^2=PA^2
(x-3)^2+(0-0)^2=(x-6)^2+(0-0)^2
(x)^2+(3)^2-2(x)(3)=(x)^2+(6)^2-2(x)(6)
{x^2 and x^2 will get canceled}
9-6x=36-9
-6x+12x=36-12
6x=27
x=27/6
Therefore, P(27/6,0) is the third vertex.
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Let the third vertex be P(x, 0)
By distance formula,
PB=PA
Squareing both sides
PB^2=PA^2
(x-3)^2+(0-0)^2=(x-6)^2+(0-0)^2
(x)^2+(3)^2-2(x)(3)=(x)^2+(6)^2-2(x)(6)
{x^2 and x^2 will get canceled}
9-6x=36-9
-6x+12x=36-12
6x=27
x=27/6
Therefore, P(27/6,0) is the third vertex.
.
.
.
__________
HOPE THIS HELPS
FOLLOW FOR MORE
#KHUSHI #UR HELPING HAND
✌
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