Question

if two zeros if the quadratic equation. x²+(a+2)x+b are 3 and 4 then find a and b​

Answer 1

Step-by-step explanation:

refer to the attachment

Answer 2

⭐Solution ⭐

✒ given here

x²+(a+3)x+b = 0.....(1)

root of this equation are 3 and 4.

✏we know ,

sum of roots = -(coefficient of x)/(coefficient of x²)

(4+3)= -(a+3)

=> -(a+3)= 7

=> a = -7-3

=> a = -10

And,

Product of roots = (constant part)/(coefficients of x²)

(3×4)= b

=> b = 12

⏩Thus:-

Value of a = -10

Value of b = 12

✏Hopes it's right and helps u.