Question

The electronic configuration of metal M is 1S2 2S2 2P6 3S1 .The formula of its oxide will be

Answer 1

here total no electrons is 11 and in the periodic table 11 electron containing element is sodium.

so the formula of sodium oxide is Na2O

hence,formula of this place will be M2O

Answer 2

The formula of its oxide is $Na_2O$

Explanation:

The given metal M has atomic number of 11 and thus contains 11 electrons is Na (sodium).

Electronic configuration of sodium:

$[Na]=1s^22s^22p^63s^1$

Sodium atom will loose one electron to gain noble gas configuration and form sodium cation with +1 charge.

$[Na^+]=1s^22s^22p^63s^0$

Electronic configuration of oxygen:

$[O]=1s^22s^22p^4$

Oxygen atom will gain two electrons to gain noble gas configuration and form oxide ion with -2 charge.

$[O^{2-}]=1s^22s^22p^6$

Here sodium is having an oxidation state of +1 called as $Na^{+}$ cation and oxide $O^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2O$.

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