If two zeros of polynomial x³+bx²+cx+d are 1+√3 and 1-√3, find its third zero
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p(x) = x3 + bx² + cx + d
a = 1 ; b = b ; c= c; d = d
let alpha = 2+√3 = sum of the zeroes
beta = 2-√3 = sum of the product of the zeroes taken in pairs
therefore gamma => product of the zeroes
= alpha x beta x gamma = d/a = d
the other zero of the polynomial is d
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Answer:We can see that zeros of the polynomial is form of α+β and α-β
therefore, third zero absolutely will be 0.
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