If two zeros of

+

– 5x - 5 are

and

then its third zero is
(A)-1
(B)1
(C)2
(D) - 2
Answers
Answered by
3
option b is your answer
alpha =√5
beta=-√5
gama =?
alpha+beta+gama=-b/a
√5-√5+gama=1
gama=1
hope it helps
lipsa44:
plz explain it
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