If two zeros of the polynomial x3-4x2-3x+12 are √3and-√3
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If √3 and -√3 are two zeroes,
then x-√3 and x+√3 are two of its factors......
This implies that (x-√3)(x+√3)= x^2-3 is also a factor...
Dividing p(x) by x^2-3,
We get x-4 as the quotient....
Therefore,
x-4=0
x=4
Therefore the third zero is 4
You can see the steps of division in the adjoining file......
Hope it helps...!
Plz mark as brainliest
then x-√3 and x+√3 are two of its factors......
This implies that (x-√3)(x+√3)= x^2-3 is also a factor...
Dividing p(x) by x^2-3,
We get x-4 as the quotient....
Therefore,
x-4=0
x=4
Therefore the third zero is 4
You can see the steps of division in the adjoining file......
Hope it helps...!
Plz mark as brainliest
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