If two zeros of the polynomial x3-4x2-3x+12 are root 3 and -root3,then find its third zero by using alpha and beta
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sum of zeroes = 4
√3 -√3 + a + b= 4
a+ b= 4
product = -12
√3(-√3)ab= -12
3ab= 12
ab= 4
a( 4- a)= 4
a^2 - 4a +4= 0
a^2 -2 a -2a +4 = 0
a( a-2) -2( a-2)= 0
a= 2
b=4-2= 2
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