If U={a,b,c,d,e,f,g,h},A={b;d,f,h},B={a,d,e,h}1.A' 2.B' 3.A'intersection B' 4.A'unionB' 5.(A union B)' 6.(A intersection B)' 7.(A')' 8.(B')'
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U={a,b c d e f g h} , A={b d f h} ,B={a d e h}
1.A' = U - A
= {a,c,e,g}
2.B' = U-B
= {b,c,f,g}
3.A' intersection B'
= {a,c,e,g} intersection {b,c,f,g}
= {c,g}
4.A' union B'
={a,c,e,g} union {b,c,f,g}
={a,b,c,e,f,g}
5.(A union B)'
=A={b,d,f,h}
= B= {a,d,e,h}
= A union B
={a,b,d,e,f,h}
(A union B)' = U - A union B
= {a,b,c,d,e,f,g,h} - {a,b,d,e,f,h}
={c,g}
6.(A intersection B)'
=A intersection B = {d,h}
= (A intersection B)' = U - A intersection B
= {a,b,c,e,f,g}
7.(A')'
= A' = U - A
= {a,c,e,g}
(A')'= U-A'
= {a,b,c,d,e,f,g,h} - {a,c,e,g}
={b,d,f,h}
8.(B')'
=B' = U - B
{a,b,c,d,e,f,g,h} - {a,d,e,h}
= {b,c,f,g}
(B')' = U - B'
{a,b,c,d,e,f,g,h} - {b,c,f,g}
= {a,d,e,h}
Here is ur answer dear
May this help uh
1.A' = U - A
= {a,c,e,g}
2.B' = U-B
= {b,c,f,g}
3.A' intersection B'
= {a,c,e,g} intersection {b,c,f,g}
= {c,g}
4.A' union B'
={a,c,e,g} union {b,c,f,g}
={a,b,c,e,f,g}
5.(A union B)'
=A={b,d,f,h}
= B= {a,d,e,h}
= A union B
={a,b,d,e,f,h}
(A union B)' = U - A union B
= {a,b,c,d,e,f,g,h} - {a,b,d,e,f,h}
={c,g}
6.(A intersection B)'
=A intersection B = {d,h}
= (A intersection B)' = U - A intersection B
= {a,b,c,e,f,g}
7.(A')'
= A' = U - A
= {a,c,e,g}
(A')'= U-A'
= {a,b,c,d,e,f,g,h} - {a,c,e,g}
={b,d,f,h}
8.(B')'
=B' = U - B
{a,b,c,d,e,f,g,h} - {a,d,e,h}
= {b,c,f,g}
(B')' = U - B'
{a,b,c,d,e,f,g,h} - {b,c,f,g}
= {a,d,e,h}
Here is ur answer dear
May this help uh
jesuraja917:
isnt it
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