Question

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Answer 1

Answer:

Volume of water displaced out = Volume of the solid immersed in

Volume of the solid = Volume of the cone + Volume of the hemisphere

∴ volume of cone =

$\frac{1}{3} {\pi \: r}^{2} h$

$\frac{1}{3} \times \frac{22}{7} \times 6 \times 6 \times 12$

$\frac{3168}{7} = 452.57 {cm}^{3}$

volume of hemisphere =

$\frac{2}{3} {\pi \: r}^{3}$

$\frac{2}{3} \times \frac{22}{7} \times 6 \times 6 \times 6$

$\frac{3168}{7} = 452.57 {cm}^{3}$

∴ The volume of water displaced out = Volume of the solid

= (1) + (2)

= 905.14 cm3

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