Question

if u are a genius then prove by giving ans of 2,3,4 and 5 questions

Answer 1

answer of 2 is
$\sqrt{ {30}^{2} + {24}^{2} + {18}^{2} }$
= 42.4 cm

For the answer of 4
volume of cuboid = L*B*H = 840 sq. cm
L = 14
B = 5
H = volume/(Length*Breadth)
= 840/70 = 12 cm

Answer of 5
LSA of cylinder = 2πrh
=2*(22/7)*7*13.5
=44*13.5 =594 sq. cm

TSA of cylinder = 2πr(r+h)
=2*(22/7)*7*(13.5+7)
=2*22*20.5
=902 sq. cm

Answer 2

(2) for maximum length of rod that can be kept in a cuboidal box of sides 30cm,24cm and 18cm
we will have to find the length of diagonal
diagonal of cuboid=√l²+h²+b²
= √(30)²+(24)²+(18)²
=√900+576+324
=√1800
=42.43cm
(3) diameter of conical vessel= 14cm
therefore, radius= 7cm
slant height of vessel is 25 cm

l=√r²+h²
l²=r²+h²
(25)²=(7)²+h²
625-49=h²
576=h²
h=√576
h=24cm
for finding capacity
we have to find volume
volume of cone = 1/3πr²h
=1/3×22/7×7×7×24
=1/3×22×7×24
=1/3×3696
=1232cm³
in litres
1cm³=1/1000litres
1232cm³=0.1232litres
(4) volume of cuboid is 840cm³
length=14cm
breadth=5cm
height=?
volume of cuboid=l×b×h
840=14×5×h
840= 70×h
h=840/70
h=12cm

(5) height of cylinder =13.5cm
radius =7cm
CSA of cylinder =2πrh
=2×22/7×7×13.5
=2×22×13.5
=44×13.5
=594 cm2
TSA of cylinder =2πr(r+h)
=2×22/7×7(7+13.5)
=2×22(20.5)
=44×20.5
=902cm²