Question

If u bar=2icap-2jcap+3kcap is the initial velocity of a body vBar=2icap-4jcap+5kcap is the final velocity which attains in a time of 10s,then its acceleration vector is

Answer 1

Answer:

Its acceleration vector is, a bar= (1/5)jcap- (1/5)kcap

Explanation:

Here,

Initial velocity, u bar=2icap-2jcap+3kcap

Final Velocity, v bar=2icap-4jcap+5kcap

Time, T= 10s

Acceleration Vector = a bar

We know,

v bar=u bar +a bar×T

√ a bar×T= v bar- u bar

√ a bar= (v bar- u bar)/T

√ a bar= (2icap-2jcap+3kcap-2icap+4jcap-5kcap)/10

√ a bar= (2jcap-2kcap)/10

√ a bar= (1/5)jcap-(1/5)kcap