Physics, asked by ayushi708, 1 year ago

if u is the initial velocity of a body and a the acceleration the value of distance travelled by nth second is

Answers

Answered by Anonymous
15
hey dear
here is your answer

initial velocity = u

acceleration = a

distance travelled in nth second = Sn

so,

Sn = u+a/2(2n-1)

hope it helps :)
Answered by DevilDoll12
5
HEYA!
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Using the fourth equation of motion,

sn = u + \frac{a}{2} (2n - 1)
Which is the distance travelled .

Here , Sn: distance travelled in nth second .

u is the initial velocity.

a is the acceleration

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