Question

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My question is:

A paper is in the form of a rectangle ABCD in which AB= 20cm, BC =14cm. A semi-circular portion with BC as diameter is cut off.Find the area of the remaining part. (Use π=22/7)

Answer 1

Hey mate, here is your answer-:)

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$Area \: of \: remaining \: part = Area \: of \: rectangle - Area \: of \: semi-circle \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 14 - \frac{22 \times 7 \times 7}{7 \times 2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 280 - \frac{154}{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 280 - 77 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 203 {cm}^{2}$

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HOPE it helps to you!!!

Answer 2

YOUR ANSWER IS 230 cm².

HOPE IT HELPS YOU