if u solve this than u will become a 101% branilist
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Incredible29:
its very easy bro
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Heya user ,
Here is your answer !!
___________
( x + 2 ) is a factor of ( x³ + 13x² + 32x + 20 ) .
So , dividing ( x³ + 13x² + 32x + 20 ) by ( x + 2 ) ,
we get , another factor ( x² + 11x + 10 )
Now , we can also middle term factorise the term ( x² + 11x + 10 ) .
x² + 11x + 10
= x² + 10x + x + 10
= x ( x + 10 ) + 1 ( x + 10 ) .
= ( x + 1 ) ( x + 10 ) .
So , the factors of ( x³ + 13x² + 32x + 20 ) are ----->
( a ) ( x + 1 ) .
( b ) ( x + 10 ) .
( c ) ( x + 2 ) .
___________
Hope it helps !!
Here is your answer !!
___________
( x + 2 ) is a factor of ( x³ + 13x² + 32x + 20 ) .
So , dividing ( x³ + 13x² + 32x + 20 ) by ( x + 2 ) ,
we get , another factor ( x² + 11x + 10 )
Now , we can also middle term factorise the term ( x² + 11x + 10 ) .
x² + 11x + 10
= x² + 10x + x + 10
= x ( x + 10 ) + 1 ( x + 10 ) .
= ( x + 1 ) ( x + 10 ) .
So , the factors of ( x³ + 13x² + 32x + 20 ) are ----->
( a ) ( x + 1 ) .
( b ) ( x + 10 ) .
( c ) ( x + 2 ) .
___________
Hope it helps !!
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