Question

if u1 = u2 = u for two projectiles, and these two projectiles are thrown at angles θ1 and θ2 and cover the same horizontal distance xt, so land at the same point. find a relation between θ1 and θ2.

Answer 1

as We know that ,

Horizontal distance = u0^2×sin2θ/g

Since Horizontal distance is same in both the case,

Hence:

u1^2×sin2θ1/g   =  u2^2× sinθ2/g

since we have

u1= u2 =u

 eliminating the common terms we will get

sin2θ1  =  sin2θ2

2θ1 = 360+2θ2

dividing both sides

θ1 = θ2 + 180