if unit vector ICAP is rotated through an angle of 30 degree clockwise then new vector of obtained
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The i cap on rotating 30 degree in the clockwise direction will lie in the x-y plane and will also have (-j) cap value in its vector.
Thus on rotating the i cap in 30 degree clockwise we will get 2 components among which one will be cos30 icap and the other will be (-j)cap sin(90-60).
So, the vector will be √3/2 icap - 1/2jcap.
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