Physics, asked by prathapjollyguy713, 8 months ago

If v =a\t+bt2+ct3 where v is velocity, t is time and a,b,c are constant then find dimensions of ab\c​

Answers

Answered by mokshawalgude
9

Answer:

Formula = v=a/t

We know that dimensions of velocity is LT^-1

Time is T

v = CT^3

=LT^-1 *T^-3

= LT^ -4

a= v * t

=LT^-1*T

a= L

v=a/t+bt^2

v=bt^2

b= v/T^2

=LT^ -1/T^2

=LT^ -3

b= LT^ -3

Hope it helps!!!☺️☺️

Answered by brainliest2877
2

Answer:

here is ur answer

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similarly u can find all a.b.c

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