if v is the volume of a cubiod x,y,z and A is its surface area then A/V.
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The dimensions of the cuboid are a,b,c.
We know that, Volume of the cuboid V=abc and surface area of the cuboid S=2(ab+bc+ac)
To prove:
V
1
=
S
2
[
a
1
+
b
1
+
c
1
]
Consider LHS,
V
1
=
abc
1
...(1)
Consider RHS.
S
2
[
a
1
+
b
1
+
c
1
]=
2(ab+bc+ac)
2
[
a
1
+
b
1
+
c
1
]
=
ab+bc+ac
1
[
a
1
+
b
1
+
c
1
]
=
ab+bc+ac
1
[
abc
ab+bc+ac
]
=
abc
1
S
2
[
a
1
+
b
1
+
c
1
]=
abc
1
...(2)
Hence from (1) and (2) we get
V
1
=
S
2
[
a
1
+
b
1
+
c
1
]
I hope it may helps you
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