Question

If V is the volume of a cuboid of dimensions
a x b × c and S is its surface area, then
prove that 1/V=2/S[1/a+1/b+1/c]​

Answer 1

Answer:

Surface area(S) =2(ab+bc+ca)

V=volume=abc

2/S(1/a+1/b+1/c)=2/S(bc+ca+ab)/abc

=2/S(S/2)/abc=1/abc=1/V