If v is the volume of a cuboid of dimensions l,b,h and s is its surface area ,then prove that 1/v = 2/s (1/l + 1/b +1/h)
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Answered by
31
s = 2(lb + bh + hl) ( there are six faces)
divide the equation by lbh
s/lbh = 2(1/l + 1/b + 1/h)
lbh = v
take S on the other side to get:
1/v = 2/s(1/l + 1/b + 1/h)
divide the equation by lbh
s/lbh = 2(1/l + 1/b + 1/h)
lbh = v
take S on the other side to get:
1/v = 2/s(1/l + 1/b + 1/h)
Answered by
15
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