if 'v' is volume of cuboid of dimensions a, b, c and 'S' is its surface area than prove that 1/v=2/S(1/a +1/b+1/c)
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Hi ,
a , b , c are dimensions of the
cuboid.
S = 2 ( ab + bc + ca )
V = abc
RHS = 2/S(1/a + 1/b + 1/c )
= 2/[ 2( ab+bc+ca )] { 1/a+ 1/b + 1/c}
= 1/( ab+ bc +ca ) {( bc + ac + ab )/abc }
= 1/abc
= 1/V
= LHS
I hope this helps you.
:)
a , b , c are dimensions of the
cuboid.
S = 2 ( ab + bc + ca )
V = abc
RHS = 2/S(1/a + 1/b + 1/c )
= 2/[ 2( ab+bc+ca )] { 1/a+ 1/b + 1/c}
= 1/( ab+ bc +ca ) {( bc + ac + ab )/abc }
= 1/abc
= 1/V
= LHS
I hope this helps you.
:)
kusum43:
thnx
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