Question

If v - Vm sin (wt) and i= Im sin (wt + 30
then current is
to Voltage​

Answer 1

Answer:

the answer will be 30+20=50

Answer 2

Answer:

The current is leading the voltage by 30°.

Explanation:

From the question we have,

$V=V_msin(\omega t)$        (1)

$I=I_msin(\omega t+30\textdegree)$  (2)

Where,

V=instantaneous voltage

$V_m$=peak voltage

ω=angular frequency

t=time

$I_m$=peak current

The equation (2) is of the form,

$I=I_msin(\omega t+\theta)$         (3)

Where,

θ=angle by which the current is leading the sine value

So, by comparing equation (3) with equation (1) we can say that the current is leading the voltage by 30° as both the instantaneous values are in sine waveform.