Question

if VBC - ADEF,
BC = 21 cm, then EF is equal to
ar(AABC)
ar(ADEF)
(b) 6 cm
25
(n) 9 cm
(0) 35 cm
(dl) 25 cm​

Answer 1

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Answer 2

Step-by-step explanation:

$abc \: \: - def \: {given} \\ ar(abc) = 64 {}^{2} and \: ar \: (def) = 121 {}^{2}$

$ef = 15.4cm$

$ar \times \frac{abc}{def} = \frac{ab {}^{2} }{de {}^{2} } = \frac{bc {}^{2} }{ef {}^{2} } = \frac{ac {}^{2} }{df {}^{2} }$

$\frac{64}{121} = \frac{bc {}^{2} }{(15.4) {}^{2} }$

$\frac{8}{11 } = \frac{bc}{15.4}$

$8 \times \frac{154}{11} = bc = 11.2$