if vector A is equal to 2 i CAP + 3 j cap - 6 k
cap , vector B equals to - i CAP + 2 j cap + 3 k cap. find angle between vector a and vector a * vector b.
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Answer:
Given:
a
=2
i
^
+
j
^
−3
k
^
and
b
=3
i
^
−2
j
^
−
k
^
a
.
b
=(2
i
^
+
j
^
−3
k
^
)(3
i
^
−2
j
^
−
k
^
)
=6−2+3=7....(1)
∣
a
∣=
2
2
+1
2
+(−3)
2
=
14
....(2)
∣
∣
∣
∣
b
∣
∣
∣
∣
=
3
2
+(−2)
2
+(−1)
2
=
14
....(3)
cosθ=
∣
a
∣.
∣
∣
∣
∣
b
∣
∣
∣
∣
a
.
b
=
14
14
7
=
2
1
cosθ=cos60
o
θ=60
o
Hence the required angle is 60
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