Question

If vector A+ vector B = Vector C and the angle between Vector A and B is 120 degree, then find the magnitude of vector C..

Answer 1

Step-by-step explanation:

i think your question is incomplete

Answer 2

The magnitude of vector C  will be $\sqrt{A^{2} +B^{2} -AB}$.

Step-by-step explanation:

Given:
vector A+ vector B = Vector C .

The angle between Vector A and B is 120 degree.

To Find:

The magnitude of vector C.

Solution:

As given-vector A+ vector B = Vector C.

Vector C is resultant vector of vector A and  vector B.

Magnitude of vector A = A , Magnitude of vector A

Magnitude of vector C =C

As given -the angle between Vector A and B is 120 degree.

$C=\sqrt{A^{2} +B^{2} +2AB \ Cos120\textdegree}$

    $=\sqrt{A^{2} +B^{2} +2AB (-\frac{1}{2} )}$

  $=\sqrt{A^{2} +B^{2} -AB }$

Thus,the magnitude of vector C  will be $\sqrt{A^{2} +B^{2} -AB}$.

PROJECT CODE#SPJ3