If vector a, vector b, vector c are any three vectors, show that vector a×(vector b+ vector c)=vector a× vector b+ vector a× vector
c.
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Answered by
9
Hey
Now, vector a+vector b+vector c=0
Taking cross product with vector a
Hence, vector a × vector a + vector a × vector b + vector a × vector c =0 ….. (I)
Vector a × vector a= 0
Hence, Expression (I) becomes……
0+vector a × vector b + vector a × vector c = 0
Hence, vector a × vector b = vector c × vector a
As, vector a × vector b = vector c × vector a
Hence, vector a × vector b = vector c × vector a.
i hope its help you
Now, vector a+vector b+vector c=0
Taking cross product with vector a
Hence, vector a × vector a + vector a × vector b + vector a × vector c =0 ….. (I)
Vector a × vector a= 0
Hence, Expression (I) becomes……
0+vector a × vector b + vector a × vector c = 0
Hence, vector a × vector b = vector c × vector a
As, vector a × vector b = vector c × vector a
Hence, vector a × vector b = vector c × vector a.
i hope its help you
Answered by
2
We know that; Both the Dot product and Cross product follow the property of distributive law:
So;
LHS = A⃗ × (B⃗ +C⃗ )
= (A⃗ × B⃗ ) + (A⃗ × B⃗ ) = RHS
Proof:
Let d=a⃗×(b⃗+c⃗)−a⃗×b⃗−a⃗×c⃗
so it is required to prove that d=0:
d² = d⃗•d⃗
=d⃗•(a⃗×(b⃗+c⃗)−a⃗×b⃗−a⃗×c⃗)
=d⃗•(a⃗×(b⃗+c⃗))−d⃗•(a⃗×b⃗)−d⃗•(a⃗×c⃗)
=(d⃗×a⃗)•(b⃗+c⃗)−(d⃗×a⃗)•b⃗−(d⃗×a⃗)•c⃗
=(d⃗×a⃗)•(b⃗+c⃗)−(d⃗×a⃗)•(b⃗+c⃗)
=0
Therefore d=0, so a⃗×(b⃗+c⃗)=(a⃗×b⃗)+(a⃗×c⃗)
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