Question

If vector for 4i + 6 j and vector b equal to 3i + 4 k then component of a along b

Answer 1

acos@

Where @ is the angle between a and b

Now a.b=|a||b|cos@

a.b = 12

|a|=√52

|b|=√25=5

Cos@=12/(5x√52)

Thus

acos@=12/(5x√52){4i+6j)