Question

If vectors P, Q, and R have magnitudes 5, 12, and 13 units and P+Q=R, if the angle between Q and R is theta. Then find 13/2 cos theta​

Answer 1

Answer:

Explanation:R = P + Q

13 = sqrt(5^2 + 12^2 + (2 × 5 × 12 × Cosx))

169 = 169 + 120Cosx

0 = 120Cosx

Cosx = 0

Cosx = Cos90

x = 90°

Angle between P and Q is 90°

Tan(y) = P Sinx / (Q + PCosx)

= 5 / (12 + 0)

= 5/12

y = Tan^-1 (5/12)

Angle between Q and R is Tan^-1 (5/12)

Read more on Brainly.in - https://brainly.in/question/1489635#readmore