If vectors P, Q and R have magnitudes 5, 12 and 13 units and P+ Q =R, the angle between Q and R is
in terms of cos
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Answers
Answered by
138
Answer:
The answer is 21.25 ° .
Explanation:
Solution:
P = 5
Q = 12
R = 13
To find angle between Q & R
P + Q = R
P = R - Q ( Talking square on both sides)
P2 = R2 + Q 2 - 2QRCosΘ
(5)2 = (13)2 + (12)2 -2(12)(13) CosΘ
25 = 169 + 144 - 312 CosΘ
25 - 313 = -312CosΘ
- 288 = - 312CosΘ
Minus sign cancels out on both sides.
CosΘ = 288/312
Reducing the number to the lowest.
CosΘ = 12/13
Θ = Cos-1 (12/13)
Θ = Cos-1 (0.932)
Θ = 21.25 °
Answered by
56
Answer:
|vector p |=5
|vector q |=12
|vector R|=13
cos theta = q/R =12/13
theta =cos^-1(12/13)
this is the answer
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