Question

if velocity of body is reduced to one half then its kinetic energy become one fourth .how?

Answer 1

Because

K.E=1/2mv^2

So if v'=1/2v then K.E'=1/2mv'^2

Therefore, K.E'=mv^2/4

Answer 2

we know that kinetic energy = 1/2 * m * v^2

==>  kinetic energy is directly proportional to v^2

if v is reduced to half

kinetic energy = 1/2*m*v/2*v/2

==> kinetic energy  =  1/8 *m * v^2

==> kinetic energ is reduced to 1/4th of its value

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