If velocity, v = (A/B) [1-e to the power -t/B] where t is time, A & B are constants write the dimensions of A & B
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Consider the given equation,
mu=A+λB+λ2C............(1)
Writing dimensional formula of m, u and lambda
Dimension of mu=[MLT−1]
Dimension of wavelength=[L]
Since, dimension of same quantity adds.
Put dimensions in (1)
[MLT−1]=A
[MLT−1][L]=B
[ML2T−1]=B
[MLT−1][L2]=C
[ML3T−1]=C
Dimension of A,B and C are calculated.
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