Physics, asked by Veena1303, 10 months ago

If velocity v of a particle moving on a straig
as a function of time t is given as v = 5 - t (m/s)
then the distance covered by the particle in first
10 s is​

Answers

Answered by ayushgarg35
1
ds/dt = 5-t
ds=(5-t)dt
Now integrating both sides with limits (0-s) and (0-10) respectively for ds and dt
S=50-50
S=0
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