Question

if velocity v of a paticle moving on a straight line as a function of time t is given as v=5-tm/s then the distance covered by the particle in first 10sec​

Answer 1

Answer:

we know,

v=dx/dt

v*dt=dx

taking integration on both sides

∫ v*dt= ∫ dx

∫ (t-5)*dt= ∫ dx

t^2 /2 - 5t=x

so, x= t^2 /2 - 5t

put t= 10 sec.

x= 10*10 /2 - 5(10)

x= 50-50

x= 0m

so distance travelled by particle in first 10 sec.=0m

hope this helps...

Explanation: