If very the escape velocity from the surface of the earth then the escape velocity from the center of the earth
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To calculate gravitational potential at the center of earth, take a spherical shell element at radius r.
dV=−rGM34πR34πr2dr=−R33GMrdr
Integrating this, we get V=−23RGM
The potential at the surface of earth is −RGM
Since escape velocity is proportional to the square root of potential energy and hence square root of gravitational potential, escape velocity at centre of earth will be 23ve
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