if voltage across the given resistor is doubled then what will be changed in power consumption of a resistor?how?
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Hey.
Here is the answer.
As, P = V^2 / R
So, if voltage is doubled then V'=2V
P' = (2V)^2 / R = 4V^2/R = 4P
Hence power consumption will be four times .
Thanks.
Here is the answer.
As, P = V^2 / R
So, if voltage is doubled then V'=2V
P' = (2V)^2 / R = 4V^2/R = 4P
Hence power consumption will be four times .
Thanks.
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