Question

If volume of the cylindrical tank is 154 m² and radius of the tank is 7 m. find height. of the tank.​

Answer 1

Step-by-step explanation:

Volume of cylinder= πrsquare h

154=22÷7×49×h

154=154h

h=154÷154

h=1 ans

Answer 2

Step-by-step explanation:

Given information

• ⇀Volume of the cylindrical tank is 154m²
• ⇀ Radius of the cylindrical tank is 7m

What we have to calculate

• ⇀We have ask to calculate height of cylindrical tank

Let's calculate

➡️In this question, the volume of cylindrical tank is given (154m²) So we have to compare that volume with formula which can be expressed as

$\\ \large \longmapsto \underline{\boxed{ \bf{ \green{Volume_{(cylindrical \; tank)} \: = \pi {r}^{2} h}}}} \red\bigstar$

Where ,

• π is 22/7
• r is radius = 7
• h is height not given

Now we will substituting the values in our formula, we get

$\implies \qquad \qquad \: \sf \red{Volume_{(cylindrical \; tank)}} = \pi {r}^{2} h \\ \\ \\ \implies \qquad \qquad \: \sf \ {154}^{} = \dfrac{22}{7} \times {7}^{2} \times h \\ \\ \\\implies \qquad \qquad \: \sf \ {154} = \dfrac{22}{ \cancel7} \times 7 \times \cancel7 \times h \\ \\ \\ \implies \qquad \qquad \: \sf \ {154} = 22 \times 7 \times h \\ \\ \\ \implies \qquad \qquad \: \sf \ {154} = 154 \times h \\ \\ \\ \implies \qquad \qquad \: \sf h = \cancel \dfrac{154}{154} \\ \\ \\ \implies \qquad \qquad \: \sf \ \large \boxed{ \underline{{ \bf \: height = 1}}}$

$\\ \\ \large{ \textbf{ \textsf{ \:Hence required height of cylindrical tank is 1m }}}$

$\underline \blue{\rule{75mm}{1.5mm} }$