if water Of mass 80g and temperature 45℃ is mixed with water of mass 20g and temperature 30℃, what will be the maximum temperature of the mixture
Answers
Answered by
6
simply use q=m s ∆T and q=m l
ktalesha28:
what should be the maaa
mass*
masses r given
refer ncert
thanks : )
Answered by
10
assume that they attain a temp T.
by using the formula.
The T value will be between 35 and 45.
so..
80 × 1× (45 - T )= 20 × 1 × (T -35)
solve for T
by using the formula.
The T value will be between 35 and 45.
so..
80 × 1× (45 - T )= 20 × 1 × (T -35)
solve for T
ok
yeah u need to do so
so q(lost)= q(gain)
yup
thanks : )
use the formula provided by mockingjay1 i.e q= m ×s × change in T
hey
is the maximum temperature 50℃
no it is 43
it must be between 30 and 45
Similar questions