Question

if wavelength associated with particla A is 5 * 10^-8,calculate wavelength associated with particle B if its momentum is half of A

Answer 1

Answer:

10∧-7

Explanation:

debroglie Eq-

λ =  h/p               [h  = plank's constant]

λ(A) = 5*10∧-8

p(A) = h/5*10∧-8

but,

p(A) = 2p(B)

p(B) = (h/5*10∧-8)/2

so, λ(B) = h/p(B)

          = h/h*10∧(+7)

         = 10∧-7 Ans