Question

if wavelength
of a photon is 6000a ,then the energy of photon will be​

Answer 1

Answer:

300 Å

Explanation:

As learnt

The energy (E) of a quantum of radiation -

Where h is plank’s constant and

is frequency

-

AND

Speed of electromagnetic radiation -

where frequency is (

(pronounced as nu), wavelength is (λ) and velocity of light is(c)

We know,

E= energy of a quantum of radiation

h=plank's constant

frequency of radiation

and

Now,

Put in 2

300 Å

Answer 2

The energy of the photon is $3.31\times 10^{-19}\ J$

Explanation:

Given that,

The wavelength of a photon, $\lambda=6000\ A=6000\times 10^{-10}\ m=6\times 10^{-7}\ m$

We need to find the energy of photon. We know that the formula that is used to find the energy is given by :

$E=\dfrac{hc}{\lambda}$

Here,

h is Planck's constant

c is the speed of light

$E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{6\times 10^{-7}}\\\\E=3.31\times 10^{-19}\ J$

So, the energy of the photon is $3.31\times 10^{-19}\ J$. Hence, this is the required solution.

Learn more,

Energy of photon

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