Question

If we assume kinetic energy of a proton is equal to energy of the photon, the ratio of de Broglie wavelength of proton to photon is proportional to

Answer 1

λ=hp photon energy E=hv

So, λ1=hp=h2mE−−−−√………..(i)

⇒E=hv2=hcλ2

λ2=hcE……………(ii)

From Eqns. (i) & (ii),

λ1λ2=h2mE−−−−√(hcE)∼EE−−√=E12