If we can find out directly by pythagoras theorem like obvious base and perpendicular will be 10 also so taking ac diagonal we can get 10 root 2 then why the long process.A farmer moves along the boundary of a square field of side 10 metre in 40 second what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position
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each side =10m so periphery =40 m..he travel 40 m in 40 sec..so 10 m in 10 sec...now total time travel =(2×60 + 20)=140 sec..so he made 140/40=3 complete round and additional 20 m alog the square field..so displacement =√(10*2) + (10*2)= 2√10m
AFridiiiKhaaannn:
if the displacement eventually gonna be 10 root 2 then why we are calculation rounds here? its not necessary na here? only magnitude of displacement is asking here so taking Pythagoras eventually lead to ten root 2 ?am I wrong ? I am confuse
see u have to know the first how much linear distance travel by the farmer..if the time is not 2 min and 20 sec say 2min only then displacement will be zero..and dist will vary with time so u have to calcutate how much linear distance is travel by the man
r u getting my point
yup okay
I should take v=0 or u=0 here in this question?A car is moving at rate of 72km/h and applies brake which provide a retardation of 5ms-2. 1. How much time does ithe car take to stop. 2.how much distance does the car cover before coming to rest? 3. what would be the stopping distence needed if speed of the car is doubled?
final velocity V=0 then use equation of motion
in which class r u studying??
I got it , sorry v=0 because it will gonna stop , thanks
i am now master of this topic
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