if we divide 300 into two parts such that 1/2 of the first and 1/3 of the second are equal find the difference between the two parts.
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Let the parts be x and 300-x
So according to the question,
X/2=1/3(300-x)
X/2= 300-x/3
By cross multiplication
3x= 600-2x
5x= 600
X= 120
So the parts are 120 and 180
So according to the question,
X/2=1/3(300-x)
X/2= 300-x/3
By cross multiplication
3x= 600-2x
5x= 600
X= 120
So the parts are 120 and 180
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