Question

If we eliminate 6.25×1018 electrons from a conductor then the charge on the conductor is (a) 1C (b) 2C (c) 3C (d) 4C​

Answer 1

$\underline{ \underline{ \large\green\maltese\bf \large \red{Given:-}}}$

$\bull$Electrons Eliminated ,n= $6.25×10^{18}$

$\underline{\underline{\large\purple\maltese\bf \large \orange{To \:Find:-}}}$

$\bull$Charge on the conductor,Q

$\underline{ \underline{ \large\blue\maltese\bf \large \green{Solution:-}}}$

Since Electrons will be eliminated,body will develop a net positive Charge,

Calculating Charge-

$\underline{ \sf \red{Formula \: used:-}}$

$\boxed{q = ne}$

where,

• q= total charge
• n= number of electrons
• e= charge on electron($1.6 × 10^{-19}$)

Putting Values,

Q = $6.25×10^{18}$ × $1.6 × 10^{-19}$

Q = $6.25×1.6 × 10^{-19} ×10^{18}$

Q = $6.25×1.6 × 10^{(-19+18)}$

Q = $10 × 10^{-1}$

Q = 1 C

$\huge\star$ $\sf\blue{Charge \:on\: conductor \:will \:be\: 1 \:Coulomb}$

$\therefore$ $\sf\red{Option\: (a)1C \: is \:correct}$

Answer 2

Explanation:

option (a) 1C is write answer