Math, asked by Rajakumar6027, 1 year ago

If we permute 8 letters of the world ‘computer' in 8! ways, how many permute words have ‘p' and ‘e' next to each other

Answers

Answered by AmanRajSinghania
1
= 7! x 2! is the answer.
Answered by Chaitanya1696
0

The number of permuted words is 7! 2! = 10080

Explanation:

  • We have been given the word "computer" that has eight letters and thus will be organized in 8! ways.
  • Now, we've to search out the quantity of permuted words if 'p' and 'e' area units next to every different.
  • The things that move will be assumed as one unit.
  • Hence,  will be thought about as one unit. Thus, we've currently totaled seven units in that area unit.
  • These will be organized in 7 wayst. will be organized along in 2! ways.

Therefore, the quantity of permuted words is 7! 2! = 10080

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