if we subtract -3x the power of 2 y and the power of 2 from x the power of 2 y the power of 2
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if this is your problem:[(x2y3)4(y4)0z-2]/[(xz2)3y-5] powers to a power are multiplied and multiplication of similar bases you add exponents. Any number to 0 power is 1. If a number is raised to a negative exponent, you take reciprocal. [x8y121y5]/x3z6z2 Simplifying both numerator and denominator(x8y17)/(x3z8) division you subtract exponents so finally x5y17/z8
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Step-by-step explanation:
Multiplying equation (6) by 2 and subtracting (5) from it, we get
2x+4y−2x+y=9+1
∴y=2
Substituting in (5), we get
x=
2
1
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