Question

If we take 2.2 grams of CO 2, 6.02 x 10^21 atoms of nitrogen &
0.03gram atoms of sulphur, then the molar ratio of C, N and O
atoms will be:​

Answer 1

Answer:

we can ignore the sulfur….as it is NOT present in solution....(unless of course it was SO2, but this is NOT specified.)

Explanation:

And so we got...

χCO2=moles of carbon dioxidetotal moles in the gaseous solution

And we got with respect to dinitrogen...3.01×1021⋅dinitrogen molecules6.022×1023⋅dinitrogen molecules⋅mol−1=5.0×10−3⋅mol

....WHY DID I HALVE THE GIVEN QUANTITY of nitrogen?

χCO2=2.20⋅g44.01⋅g⋅mol−12.20⋅g44.01⋅g⋅mol−1+(5.0×10−3⋅mol)=0.91

And clearly, χN2=1−χCO2=0.091...