Question

If we take 2.2 grams of CO2,6.02^23 atoms of Nitrogen and 0.03 gram atoms of sulphur then the molar ratio of C,N and O atoms will be​

Answer 1

Explanation:

N ― 1mole

C― given mass / molar mass = 2.2/44 = 1/20

O - no. of moles= 2/3 × 1/20 = 1/30

ratio = 1/20 : 1/30: 1 = 3 : 2 :60