Question

if we take p(x) = - x2 + x - 6, then how will we draw the graph? Solve the full question. Find the value of x & y values.

Answer 1

~Quadratic FN

p(x) = -x² + x - 6

D = { -2 , -1 , 0 , 1 , 2 }

if :
x = -2 » y = -12

x = -1 » y = -9

x = 0 » y = -6

x = 1 » y = -6

x = 2 » y = -8

Range = { -12 , -9 , -8 , -6 }

Draw All The Value to the Graph :
Note : Look at The Pict