If we throw two dice,the probability that numbers are same is 1 over 6. The probability of getting two sixes is 1 over 36.find probability of :(i) two numbers being different
(ii)not getting two sixes
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1) Probability of nos being diff
= 1-(probability that no.s are same)
= 1 - 1/6
= 5/6
2) similarly,
Reqd. Probability= 1 - 1/36
=35/36
= 1-(probability that no.s are same)
= 1 - 1/6
= 5/6
2) similarly,
Reqd. Probability= 1 - 1/36
=35/36
hishamhany26:
Explain (i) plz
Can u explain plz
when 2 dice are thrown, there are 36 total possible combinations. Out of these, 6 satisfy the condition that both nos are same. .'. P(same no.) = 6/36 = 1/6. .'. P(Different no.s) = 36-6/36 = 30/36 = 5/6.
have you understood?
Yes
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