Question

If we toss two unbiased coins simultaneously, then the probability of getting no head is A/B.
Then (A+B)^2 will be equal to:

a) 21

b) 25

c)10

d)5​



answer: HH,HT,TH,TT
:•TOTAL NO.OF OUTCOMES=4
NO HEAD WILL BE OBTAINED IF YHE EVENT TT OCCURS.
:• NO.OF FAVORABLE OUTCOMES =1
:• REQUIRED PROBABILITY =1/4
BUT,GIVEN PROBABILITY =A/B
SO,A=1 AND B=4
THEREFORE,(A+B)^2=(1+4)^2=(5)^2=25
ANSWER =OPTION (B)

Answer 1

Answer:

5

Step-by-step explanation:

Answer 2

Answer:

HH,HT,TH,TT

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4NO HEAD WILL BE OBTAINED IF EVENT TT OCCURS.

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4NO HEAD WILL BE OBTAINED IF EVENT TT OCCURS.:• NO.OF FAVORABLE OUTCOMES =1

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4NO HEAD WILL BE OBTAINED IF EVENT TT OCCURS.:• NO.OF FAVORABLE OUTCOMES =1 :• REQUIRED PROBABILITY =1/4

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4NO HEAD WILL BE OBTAINED IF EVENT TT OCCURS.:• NO.OF FAVORABLE OUTCOMES =1 :• REQUIRED PROBABILITY =1/4 BUT,GIVEN PROBABILITY =A/B

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4NO HEAD WILL BE OBTAINED IF EVENT TT OCCURS.:• NO.OF FAVORABLE OUTCOMES =1 :• REQUIRED PROBABILITY =1/4 BUT,GIVEN PROBABILITY =A/BSO,A=1 AND B=4

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4NO HEAD WILL BE OBTAINED IF EVENT TT OCCURS.:• NO.OF FAVORABLE OUTCOMES =1 :• REQUIRED PROBABILITY =1/4 BUT,GIVEN PROBABILITY =A/BSO,A=1 AND B=4THEREFORE,(A+B)²=(1+4)²=(5)²=25

HH,HT,TH,TT :•TOTAL NO.OF OUTCOMES=4NO HEAD WILL BE OBTAINED IF EVENT TT OCCURS.:• NO.OF FAVORABLE OUTCOMES =1 :• REQUIRED PROBABILITY =1/4 BUT,GIVEN PROBABILITY =A/BSO,A=1 AND B=4THEREFORE,(A+B)²=(1+4)²=(5)²=25ANSWER =OPTION (B)